cos(4x)=2cos^2(2x)-1

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Solution for cos(4x)=2cos^2(2x)-1 equation: 


Simplifying
cos(4x) = 2cos2(2x) + -1

Remove parenthesis around (4x)
cos * 4x = 2cos2(2x) + -1

Reorder the terms for easier multiplication:
4cos * x = 2cos2(2x) + -1

Multiply cos * x
4cosx = 2cos2(2x) + -1

Remove parenthesis around (2x)
4cosx = 2cos2 * 2x + -1

Reorder the terms for easier multiplication:
4cosx = 2 * 2cos2 * x + -1

Multiply 2 * 2
4cosx = 4cos2 * x + -1

Multiply cos2 * x
4cosx = 4cos2x + -1

Reorder the terms:
4cosx = -1 + 4cos2x

Solving
4cosx = -1 + 4cos2x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4cos2x' to each side of the equation.
4cosx + -4cos2x = -1 + 4cos2x + -4cos2x

Combine like terms: 4cos2x + -4cos2x = 0
4cosx + -4cos2x = -1 + 0
4cosx + -4cos2x = -1

Reorder the terms:
1 + 4cosx + -4cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 4cosx + -4cos2x = 0

The solution to this equation could not be determined.

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